Integrand size = 26, antiderivative size = 170 \[ \int \sec (c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\frac {1}{8} a \left (3 a^4+10 a^2 b^2+15 b^4\right ) x-\frac {b^5 \log (\sin (c+d x))}{d}+\frac {b^5 \log (\tan (c+d x))}{d}+\frac {\left (4 b \left (5 a^4-b^4\right )+5 a \left (a^2-3 b^2\right ) \left (a^2+b^2\right ) \cot (c+d x)\right ) \sin ^2(c+d x)}{8 d}-\frac {\left (b \left (5 a^4-10 a^2 b^2+b^4\right )+a \left (a^4-10 a^2 b^2+5 b^4\right ) \cot (c+d x)\right ) \sin ^4(c+d x)}{4 d} \]
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Time = 0.24 (sec) , antiderivative size = 170, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {3167, 1819, 815, 649, 209, 266} \[ \int \sec (c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=-\frac {\sin ^4(c+d x) \left (a \left (a^4-10 a^2 b^2+5 b^4\right ) \cot (c+d x)+b \left (5 a^4-10 a^2 b^2+b^4\right )\right )}{4 d}+\frac {\sin ^2(c+d x) \left (4 b \left (5 a^4-b^4\right )+5 a \left (a^2-3 b^2\right ) \left (a^2+b^2\right ) \cot (c+d x)\right )}{8 d}+\frac {1}{8} a x \left (3 a^4+10 a^2 b^2+15 b^4\right )-\frac {b^5 \log (\sin (c+d x))}{d}+\frac {b^5 \log (\tan (c+d x))}{d} \]
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Rule 209
Rule 266
Rule 649
Rule 815
Rule 1819
Rule 3167
Rubi steps \begin{align*} \text {integral}& = -\frac {\text {Subst}\left (\int \frac {(b+a x)^5}{x \left (1+x^2\right )^3} \, dx,x,\cot (c+d x)\right )}{d} \\ & = -\frac {\left (b \left (5 a^4-10 a^2 b^2+b^4\right )+a \left (a^4-10 a^2 b^2+5 b^4\right ) \cot (c+d x)\right ) \sin ^4(c+d x)}{4 d}+\frac {\text {Subst}\left (\int \frac {-4 b^5+a \left (a^4-10 a^2 b^2-15 b^4\right ) x-20 a^4 b x^2-4 a^5 x^3}{x \left (1+x^2\right )^2} \, dx,x,\cot (c+d x)\right )}{4 d} \\ & = \frac {\left (4 b \left (5 a^4-b^4\right )+5 a \left (a^2-3 b^2\right ) \left (a^2+b^2\right ) \cot (c+d x)\right ) \sin ^2(c+d x)}{8 d}-\frac {\left (b \left (5 a^4-10 a^2 b^2+b^4\right )+a \left (a^4-10 a^2 b^2+5 b^4\right ) \cot (c+d x)\right ) \sin ^4(c+d x)}{4 d}-\frac {\text {Subst}\left (\int \frac {8 b^5+a \left (3 a^4+10 a^2 b^2+15 b^4\right ) x}{x \left (1+x^2\right )} \, dx,x,\cot (c+d x)\right )}{8 d} \\ & = \frac {\left (4 b \left (5 a^4-b^4\right )+5 a \left (a^2-3 b^2\right ) \left (a^2+b^2\right ) \cot (c+d x)\right ) \sin ^2(c+d x)}{8 d}-\frac {\left (b \left (5 a^4-10 a^2 b^2+b^4\right )+a \left (a^4-10 a^2 b^2+5 b^4\right ) \cot (c+d x)\right ) \sin ^4(c+d x)}{4 d}-\frac {\text {Subst}\left (\int \left (\frac {8 b^5}{x}+\frac {3 a^5+10 a^3 b^2+15 a b^4-8 b^5 x}{1+x^2}\right ) \, dx,x,\cot (c+d x)\right )}{8 d} \\ & = \frac {b^5 \log (\tan (c+d x))}{d}+\frac {\left (4 b \left (5 a^4-b^4\right )+5 a \left (a^2-3 b^2\right ) \left (a^2+b^2\right ) \cot (c+d x)\right ) \sin ^2(c+d x)}{8 d}-\frac {\left (b \left (5 a^4-10 a^2 b^2+b^4\right )+a \left (a^4-10 a^2 b^2+5 b^4\right ) \cot (c+d x)\right ) \sin ^4(c+d x)}{4 d}-\frac {\text {Subst}\left (\int \frac {3 a^5+10 a^3 b^2+15 a b^4-8 b^5 x}{1+x^2} \, dx,x,\cot (c+d x)\right )}{8 d} \\ & = \frac {b^5 \log (\tan (c+d x))}{d}+\frac {\left (4 b \left (5 a^4-b^4\right )+5 a \left (a^2-3 b^2\right ) \left (a^2+b^2\right ) \cot (c+d x)\right ) \sin ^2(c+d x)}{8 d}-\frac {\left (b \left (5 a^4-10 a^2 b^2+b^4\right )+a \left (a^4-10 a^2 b^2+5 b^4\right ) \cot (c+d x)\right ) \sin ^4(c+d x)}{4 d}+\frac {b^5 \text {Subst}\left (\int \frac {x}{1+x^2} \, dx,x,\cot (c+d x)\right )}{d}-\frac {\left (a \left (3 a^4+10 a^2 b^2+15 b^4\right )\right ) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\cot (c+d x)\right )}{8 d} \\ & = \frac {1}{8} a \left (3 a^4+10 a^2 b^2+15 b^4\right ) x-\frac {b^5 \log (\sin (c+d x))}{d}+\frac {b^5 \log (\tan (c+d x))}{d}+\frac {\left (4 b \left (5 a^4-b^4\right )+5 a \left (a^2-3 b^2\right ) \left (a^2+b^2\right ) \cot (c+d x)\right ) \sin ^2(c+d x)}{8 d}-\frac {\left (b \left (5 a^4-10 a^2 b^2+b^4\right )+a \left (a^4-10 a^2 b^2+5 b^4\right ) \cot (c+d x)\right ) \sin ^4(c+d x)}{4 d} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(711\) vs. \(2(170)=340\).
Time = 6.51 (sec) , antiderivative size = 711, normalized size of antiderivative = 4.18 \[ \int \sec (c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\frac {b^5 \left (\frac {\cos ^4(c+d x) (a+b \tan (c+d x))^6 \left (b^2+a b \tan (c+d x)\right )}{4 b^6 \left (a^2+b^2\right )}-\frac {\frac {\cos ^2(c+d x) (a+b \tan (c+d x))^6 \left (-3 a^2 b^2+b^2 \left (-3 a^2+2 b^2\right )+b \left (3 a b^2+a \left (-3 a^2+2 b^2\right )\right ) \tan (c+d x)\right )}{2 b^4 \left (a^2+b^2\right )}-\frac {\left (3 a^4-29 a^2 b^2+8 b^4+5 a^2 \left (3 a^2-5 b^2\right )\right ) \left (\frac {1}{2} \left (5 a^4-10 a^2 b^2+b^4+\frac {a^5-10 a^3 b^2+5 a b^4}{\sqrt {-b^2}}\right ) \log \left (\sqrt {-b^2}-b \tan (c+d x)\right )+\frac {1}{2} \left (5 a^4-10 a^2 b^2+b^4-\frac {a^5-10 a^3 b^2+5 a b^4}{\sqrt {-b^2}}\right ) \log \left (\sqrt {-b^2}+b \tan (c+d x)\right )+5 a b \left (2 a^2-b^2\right ) \tan (c+d x)+\frac {1}{2} b^2 \left (10 a^2-b^2\right ) \tan ^2(c+d x)+\frac {5}{3} a b^3 \tan ^3(c+d x)+\frac {1}{4} b^4 \tan ^4(c+d x)\right )-5 a \left (3 a^2-5 b^2\right ) \left (\frac {1}{2} \left (6 a^5-20 a^3 b^2+6 a b^4+\frac {a^6-15 a^4 b^2+15 a^2 b^4-b^6}{\sqrt {-b^2}}\right ) \log \left (\sqrt {-b^2}-b \tan (c+d x)\right )+\frac {1}{2} \left (6 a^5-20 a^3 b^2+6 a b^4-\frac {a^6-15 a^4 b^2+15 a^2 b^4-b^6}{\sqrt {-b^2}}\right ) \log \left (\sqrt {-b^2}+b \tan (c+d x)\right )+b \left (15 a^4-15 a^2 b^2+b^4\right ) \tan (c+d x)+a b^2 \left (10 a^2-3 b^2\right ) \tan ^2(c+d x)+\frac {1}{3} b^3 \left (15 a^2-b^2\right ) \tan ^3(c+d x)+\frac {3}{2} a b^4 \tan ^4(c+d x)+\frac {1}{5} b^5 \tan ^5(c+d x)\right )}{2 b^2 \left (a^2+b^2\right )}}{4 b^2 \left (a^2+b^2\right )}\right )}{d} \]
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Time = 1.55 (sec) , antiderivative size = 192, normalized size of antiderivative = 1.13
method | result | size |
derivativedivides | \(\frac {a^{5} \left (\frac {\left (\cos \left (d x +c \right )^{3}+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )-\frac {5 \cos \left (d x +c \right )^{4} a^{4} b}{4}+10 a^{3} b^{2} \left (-\frac {\sin \left (d x +c \right ) \cos \left (d x +c \right )^{3}}{4}+\frac {\sin \left (d x +c \right ) \cos \left (d x +c \right )}{8}+\frac {d x}{8}+\frac {c}{8}\right )+\frac {5 a^{2} b^{3} \sin \left (d x +c \right )^{4}}{2}+5 a \,b^{4} \left (-\frac {\left (\sin \left (d x +c \right )^{3}+\frac {3 \sin \left (d x +c \right )}{2}\right ) \cos \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )+b^{5} \left (-\frac {\sin \left (d x +c \right )^{4}}{4}-\frac {\sin \left (d x +c \right )^{2}}{2}-\ln \left (\cos \left (d x +c \right )\right )\right )}{d}\) | \(192\) |
default | \(\frac {a^{5} \left (\frac {\left (\cos \left (d x +c \right )^{3}+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )-\frac {5 \cos \left (d x +c \right )^{4} a^{4} b}{4}+10 a^{3} b^{2} \left (-\frac {\sin \left (d x +c \right ) \cos \left (d x +c \right )^{3}}{4}+\frac {\sin \left (d x +c \right ) \cos \left (d x +c \right )}{8}+\frac {d x}{8}+\frac {c}{8}\right )+\frac {5 a^{2} b^{3} \sin \left (d x +c \right )^{4}}{2}+5 a \,b^{4} \left (-\frac {\left (\sin \left (d x +c \right )^{3}+\frac {3 \sin \left (d x +c \right )}{2}\right ) \cos \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )+b^{5} \left (-\frac {\sin \left (d x +c \right )^{4}}{4}-\frac {\sin \left (d x +c \right )^{2}}{2}-\ln \left (\cos \left (d x +c \right )\right )\right )}{d}\) | \(192\) |
parts | \(\frac {a^{5} \left (\frac {\left (\cos \left (d x +c \right )^{3}+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )}{d}+\frac {b^{5} \left (-\frac {\sin \left (d x +c \right )^{4}}{4}-\frac {\sin \left (d x +c \right )^{2}}{2}-\ln \left (\cos \left (d x +c \right )\right )\right )}{d}-\frac {5 a^{4} b}{4 d \sec \left (d x +c \right )^{4}}+\frac {10 a^{3} b^{2} \left (-\frac {\sin \left (d x +c \right ) \cos \left (d x +c \right )^{3}}{4}+\frac {\sin \left (d x +c \right ) \cos \left (d x +c \right )}{8}+\frac {d x}{8}+\frac {c}{8}\right )}{d}+\frac {5 a \,b^{4} \left (-\frac {\left (\sin \left (d x +c \right )^{3}+\frac {3 \sin \left (d x +c \right )}{2}\right ) \cos \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )}{d}+\frac {5 a^{2} b^{3} \sin \left (d x +c \right )^{4}}{2 d}\) | \(206\) |
parallelrisch | \(\frac {32 b^{5} \ln \left (\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )-32 b^{5} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )-32 b^{5} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+4 \left (-5 a^{4} b -10 a^{2} b^{3}+3 b^{5}\right ) \cos \left (2 d x +2 c \right )+\left (-5 a^{4} b +10 a^{2} b^{3}-b^{5}\right ) \cos \left (4 d x +4 c \right )+a \left (a^{4}-10 a^{2} b^{2}+5 b^{4}\right ) \sin \left (4 d x +4 c \right )+8 \left (a^{5}-5 a \,b^{4}\right ) \sin \left (2 d x +2 c \right )+12 a^{5} d x +40 a^{3} b^{2} d x +60 a \,b^{4} d x +25 a^{4} b +30 a^{2} b^{3}-11 b^{5}}{32 d}\) | \(212\) |
risch | \(i x \,b^{5}+\frac {3 a^{5} x}{8}+\frac {5 a^{3} b^{2} x}{4}+\frac {15 a \,b^{4} x}{8}-\frac {5 \,{\mathrm e}^{2 i \left (d x +c \right )} a^{4} b}{16 d}-\frac {5 \,{\mathrm e}^{2 i \left (d x +c \right )} a^{2} b^{3}}{8 d}+\frac {3 \,{\mathrm e}^{2 i \left (d x +c \right )} b^{5}}{16 d}+\frac {i {\mathrm e}^{-2 i \left (d x +c \right )} a^{5}}{8 d}+\frac {2 i b^{5} c}{d}-\frac {5 \,{\mathrm e}^{-2 i \left (d x +c \right )} a^{4} b}{16 d}-\frac {5 \,{\mathrm e}^{-2 i \left (d x +c \right )} a^{2} b^{3}}{8 d}+\frac {3 \,{\mathrm e}^{-2 i \left (d x +c \right )} b^{5}}{16 d}-\frac {5 i {\mathrm e}^{-2 i \left (d x +c \right )} a \,b^{4}}{8 d}-\frac {i {\mathrm e}^{2 i \left (d x +c \right )} a^{5}}{8 d}+\frac {5 i {\mathrm e}^{2 i \left (d x +c \right )} a \,b^{4}}{8 d}-\frac {b^{5} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{d}-\frac {5 a^{4} b \cos \left (4 d x +4 c \right )}{32 d}+\frac {5 a^{2} b^{3} \cos \left (4 d x +4 c \right )}{16 d}-\frac {b^{5} \cos \left (4 d x +4 c \right )}{32 d}+\frac {a^{5} \sin \left (4 d x +4 c \right )}{32 d}-\frac {5 a^{3} \sin \left (4 d x +4 c \right ) b^{2}}{16 d}+\frac {5 a \sin \left (4 d x +4 c \right ) b^{4}}{32 d}\) | \(355\) |
norman | \(\frac {\left (\frac {3}{8} a^{5}+\frac {5}{4} a^{3} b^{2}+\frac {15}{8} a \,b^{4}\right ) x +\left (\frac {3}{8} a^{5}+\frac {5}{4} a^{3} b^{2}+\frac {15}{8} a \,b^{4}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{10}+\left (\frac {15}{4} a^{5}+\frac {25}{2} a^{3} b^{2}+\frac {75}{4} a \,b^{4}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}+\left (\frac {15}{4} a^{5}+\frac {25}{2} a^{3} b^{2}+\frac {75}{4} a \,b^{4}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}+\left (\frac {15}{8} a^{5}+\frac {25}{4} a^{3} b^{2}+\frac {75}{8} a \,b^{4}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+\left (\frac {15}{8} a^{5}+\frac {25}{4} a^{3} b^{2}+\frac {75}{8} a \,b^{4}\right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{8}+\frac {\left (10 a^{4} b -2 b^{5}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{d}+\frac {\left (10 a^{4} b -2 b^{5}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{8}}{d}+\frac {10 \left (a^{4} b +4 a^{2} b^{3}-b^{5}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{d}+\frac {10 \left (a^{4} b +4 a^{2} b^{3}-b^{5}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}}{d}+\frac {5 a \left (a^{4}-2 a^{2} b^{2}-3 b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{4 d}-\frac {5 a \left (a^{4}-2 a^{2} b^{2}-3 b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{9}}{4 d}+\frac {a \left (a^{4}+30 a^{2} b^{2}-35 b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{2 d}-\frac {a \left (a^{4}+30 a^{2} b^{2}-35 b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}}{2 d}}{\left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{5}}+\frac {b^{5} \ln \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )}{d}-\frac {b^{5} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{d}-\frac {b^{5} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{d}\) | \(525\) |
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Time = 0.26 (sec) , antiderivative size = 160, normalized size of antiderivative = 0.94 \[ \int \sec (c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=-\frac {8 \, b^{5} \log \left (-\cos \left (d x + c\right )\right ) + 2 \, {\left (5 \, a^{4} b - 10 \, a^{2} b^{3} + b^{5}\right )} \cos \left (d x + c\right )^{4} - {\left (3 \, a^{5} + 10 \, a^{3} b^{2} + 15 \, a b^{4}\right )} d x + 8 \, {\left (5 \, a^{2} b^{3} - b^{5}\right )} \cos \left (d x + c\right )^{2} - {\left (2 \, {\left (a^{5} - 10 \, a^{3} b^{2} + 5 \, a b^{4}\right )} \cos \left (d x + c\right )^{3} + {\left (3 \, a^{5} + 10 \, a^{3} b^{2} - 25 \, a b^{4}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{8 \, d} \]
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\[ \int \sec (c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\int \left (a \cos {\left (c + d x \right )} + b \sin {\left (c + d x \right )}\right )^{5} \sec {\left (c + d x \right )}\, dx \]
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Time = 0.21 (sec) , antiderivative size = 170, normalized size of antiderivative = 1.00 \[ \int \sec (c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\frac {80 \, a^{2} b^{3} \sin \left (d x + c\right )^{4} - 40 \, {\left (\sin \left (d x + c\right )^{2} - 1\right )}^{2} a^{4} b + {\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} a^{5} + 10 \, {\left (4 \, d x + 4 \, c - \sin \left (4 \, d x + 4 \, c\right )\right )} a^{3} b^{2} + 5 \, {\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) - 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} a b^{4} - 8 \, {\left (\sin \left (d x + c\right )^{4} + 2 \, \sin \left (d x + c\right )^{2} + 2 \, \log \left (\sin \left (d x + c\right )^{2} - 1\right )\right )} b^{5}}{32 \, d} \]
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Time = 0.51 (sec) , antiderivative size = 199, normalized size of antiderivative = 1.17 \[ \int \sec (c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\frac {4 \, b^{5} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) + {\left (3 \, a^{5} + 10 \, a^{3} b^{2} + 15 \, a b^{4}\right )} {\left (d x + c\right )} - \frac {6 \, b^{5} \tan \left (d x + c\right )^{4} - 3 \, a^{5} \tan \left (d x + c\right )^{3} - 10 \, a^{3} b^{2} \tan \left (d x + c\right )^{3} + 25 \, a b^{4} \tan \left (d x + c\right )^{3} + 40 \, a^{2} b^{3} \tan \left (d x + c\right )^{2} + 4 \, b^{5} \tan \left (d x + c\right )^{2} - 5 \, a^{5} \tan \left (d x + c\right ) + 10 \, a^{3} b^{2} \tan \left (d x + c\right ) + 15 \, a b^{4} \tan \left (d x + c\right ) + 10 \, a^{4} b + 20 \, a^{2} b^{3}}{{\left (\tan \left (d x + c\right )^{2} + 1\right )}^{2}}}{8 \, d} \]
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Time = 24.93 (sec) , antiderivative size = 297, normalized size of antiderivative = 1.75 \[ \int \sec (c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\frac {4\,b^5\,\ln \left (\frac {1}{{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}\right )-4\,b^5\,\ln \left (\frac {\cos \left (c+d\,x\right )}{\cos \left (c+d\,x\right )+1}\right )+3\,a^5\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )+\frac {3\,b^5\,\cos \left (2\,c+2\,d\,x\right )}{2}-\frac {b^5\,\cos \left (4\,c+4\,d\,x\right )}{8}+a^5\,\sin \left (2\,c+2\,d\,x\right )+\frac {a^5\,\sin \left (4\,c+4\,d\,x\right )}{8}+15\,a\,b^4\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )-\frac {5\,a^4\,b\,\cos \left (2\,c+2\,d\,x\right )}{2}-\frac {5\,a^4\,b\,\cos \left (4\,c+4\,d\,x\right )}{8}-5\,a\,b^4\,\sin \left (2\,c+2\,d\,x\right )+\frac {5\,a\,b^4\,\sin \left (4\,c+4\,d\,x\right )}{8}+10\,a^3\,b^2\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )-5\,a^2\,b^3\,\cos \left (2\,c+2\,d\,x\right )+\frac {5\,a^2\,b^3\,\cos \left (4\,c+4\,d\,x\right )}{4}-\frac {5\,a^3\,b^2\,\sin \left (4\,c+4\,d\,x\right )}{4}}{4\,d} \]
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